(6-y)^2+y^2=1

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Solution for (6-y)^2+y^2=1 equation: 



(6-y)^2+y^2=1

We move all terms to the left:

(6-y)^2+y^2-(1)=0

We add all the numbers together, and all the variables

y^2+(-1y+6)^2-1=0

We move all terms containing y to the left, all other terms to the right

y^2+(-1y+6)^2=1

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